## Algebra and Trigonometry 10th Edition

Published by Cengage Learning

# Chapter 4 - 4.3 - Conics - 4.3 Exercises - Page 337: 12

#### Answer

The equation matches with the graph labeled as (d).

#### Work Step by Step

$x^2-\frac{y^2}{9}=1$ $\frac{(x-0)^2}{1^2}-\frac{(y-0)^2}{3^2}=1$ It is a hyperbola with center at origin $(0,0)$ and the transverse axis is horizontal.

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