## Algebra and Trigonometry 10th Edition

Mathematical model: $F=1833.33x$ If $x=0.16~m$: $F=293.33~N$
Applied force: $F$ Distance: $x$ $F=kx$ When $x=0.12~m$, $F=220~N$ $220=k(0.12)$ $k=\frac{220}{0.12}=1833.33~\frac{N}{m}$ Mathematical model: $F=1833.33x$ If $x=0.16~m$: $F=1833.33\times0.16=293.33~N$