Answer
$z=\frac{2x^2}{3y}$
Work Step by Step
$z=k\frac{x^2}{y}$
$z=6$ when $x=6$ and $y=4$:
$6=k\frac{6^2}{4}=k\frac{36}{4}=9k$
$k=\frac{6}{9}=\frac{2}{3}$
Then:
$z=\frac{2}{3}\frac{x^2}{y}=\frac{2x^2}{3y}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 3 - 3.5 - Mathematical Modeling and Variation - 3.5 Exercises - Page 296: 60
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