Answer
$g(x)$ has zeros at $x=r_1+5,~x=r_2+5,~and~x=r_3+5$
Work Step by Step
We have that: $f(r_1)=f(r_2)=f(r_3)=0$
$g(r_1+5)=f(r_1+5-5)=f(r_1)=0$
$g(r_2+5)=f(r_2+5-5)=f(r_2)=0$
$g(r_3+5)=f(r_3+5-5)=f(r_3)=0$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 3 - 3.4 - Zeroes of Polynomial Functions - 3.4 Exercises - Page 286: 111
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