$g(x)$ has zeros at $x=r_1,~x=r_2,~and~x=r_3$
Work Step by Step
We have that: $f(r_1)=f(r_2)=f(r_3)=0$ $g(r_1)=-f(r_1)=-0=0$ $g(r_2)=-f(r_2)=-0=0$ $g(r_3)=-f(r_3)=-0=0$
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