Answer
$f(x)=(x+7i)(x-7i)$
The zeros:
$x=-7i$
$x=7i$
Work Step by Step
$f(x)=x^2+49$
$f(x)=x^2-(7i)^2$
$f(x)=(x+7i)(x-7i)$
The zeros:
$0=(x+7i)(x-7i)$
$x+7i=0$
$x=-7i$
$x-7i=0$
$x=7i$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 3 - 3.4 - Zeroes of Polynomial Functions - 3.4 Exercises - Page 284: 62
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