$f(x)=(x+6i)(x-6i)$ The zeros: $x=-6i$ $x=6i$
Work Step by Step
$f(x)=x^2+36$ $f(x)=x^2-(6i)^2$ $f(x)=(x+6i)(x-6i)$ The zeros: $0=(x+6i)(x-6i)$ $x+6i=0$ $x=-6i$ $x-6i=0$ $x=6i$
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