Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - Review Exercises - Page 234: 72


$x+2$ Domain of the function $f$ is: $[ 2, \infty)$. Domain of the inverse of function $f$ is: $[0, \infty)$.

Work Step by Step

We have $y=|x-2|=x-2$ or, $x=y-2$ or, $y=x+2$ Replace $y$ with $f^{-1} (x)$. so, $f^{-1} (x)=x+2$
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