## Algebra and Trigonometry 10th Edition

$x+2$ Domain of the function $f$ is: $[ 2, \infty)$. Domain of the inverse of function $f$ is: $[0, \infty)$.
We have $y=|x-2|=x-2$ or, $x=y-2$ or, $y=x+2$ Replace $y$ with $f^{-1} (x)$. so, $f^{-1} (x)=x+2$