Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - Review Exercises - Page 234: 41



Work Step by Step

We have $f(-x) =2(-x)\sqrt {(-x)^2+3}$ or, $=-2x\sqrt {x^2+3}$ so, $f(-x) \ne f(x)$ Thus, $f(-x) = -f(x)$
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