## Algebra and Trigonometry 10th Edition

$(f o g)^{-1} (x)=\dfrac{x}{4}-6$
We have $f(g(x))=f(x+6)$ or, $=4(x+6)$ or, $=4x+(6)(4)$ or, $y=4x+24$ Interchanging $x$ and $y$: $x=4y +24$ $\implies \dfrac{x}{4}=y+6$ or, $y=\dfrac{x}{4}-6$ Replace $y$ with $(f o g)^{-1} (x)$ $(f o g)^{-1} (x)=\dfrac{x}{4}-6$