## Algebra and Trigonometry 10th Edition

Published by Cengage Learning

# Chapter 2 - P.S. Problem Solving - Page 239: 3c

#### Answer

Neither even nor odd.

#### Work Step by Step

Suppose $f$ to be even and $g$ to be odd. Thus, $(f+g)(-x)=f(-x) +g(-x)$ or, $=f(x) +g(-x)$ or, $=f(x)+[-g(x)]$ Therefore, the sum of an even function and an odd function is neither even nor odd.

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