Answer
Neither even nor odd.
Work Step by Step
Suppose $f$ to be even and $g$ to be odd.
Thus, $(f+g)(-x)=f(-x) +g(-x)$
or, $=f(x) +g(-x)$
or, $=f(x)+[-g(x)]$
Therefore, the sum of an even function and an odd function is neither even nor odd.
