Answer
a) See graph
b) $x=-2.1213,x=2.1213$
Work Step by Step
We are given the function:
$f(x)=\dfrac{2x^2-9}{3-x}$
a) Graph the function.
From the graph the zeroes are:
$x\approx -2.121,x\approx 2.121$
b) Determine the zeros algebraically:
$f(x)=0$
$\dfrac{2x^2-9}{3-x}=0$
$2x^2-9=0$
$x^2=\dfrac{9}{2}$
$x=\pm\dfrac{3}{\sqrt 2}=\pm 2.1213$
