Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - 2.3 - Analyzing Graphs of Functions - 2.3 Exercises - Page 194: 18


$x=\frac{2}{3}$ $x=-8$

Work Step by Step

$f(x)=0$ $3x^2+22x-16=0$ ($a=3,b=22,c=-16$): $x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-22±\sqrt {22^2-4(3)(-16)}}{2(3)}=\frac{-22±\sqrt {676}}{6}=\frac{-22±26}{6}$ $x=\frac{4}{6}=\frac{2}{3}$ or $x=\frac{-48}{6}=-8$
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