## Algebra and Trigonometry 10th Edition

$45x-0.15x^2$, where $x\gt 100$
The profit function $P(x)$ is a function of the revenue function $R(x)$ and the cost function $C(x)$. Determine the revenue function: $R(x)=[90-(x-100)(0.15)]x$ $=(90-0.15x+15)x$ $=(105-0.15x)x$ $=105x-0.15x^2$ Determine the cost function: $C(x)=60x$ Determine the profit function: $P(x)=105x-0.15x^2-60x$ $=45x-0.15x^2$, where $x\gt 100$