Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - 2.2 - Functions - 2.2 Exercises - Page 183: 35



Work Step by Step

$f(x)=15-3x$ Since we are solving for all the real values of $x$ when $f(x) = 0$, set the function $f(x)=15-3x$ equal to zero and we get the following equation: $15-3x=0$ Now subtract 15 from both sides of the equation so that all of the constants are on the right side of the equation and all of the $x$ terms are on the left side. $15-3x-15=0-15$ $-3x=-15$ Once all of the constants are on the right and all the $x$ terms are on the left, solve for $x$ by dividing both sides by $-3$. $\frac{-3x}{-3}=\frac{-15}{-3}$ $x=5$
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