## Algebra and Trigonometry 10th Edition

In a linear equation $y=mx+b$, $m$ is the slope and $(0,b)$ the y-intercept. That is, the y-intercept is the point on the line when $x=0$ $5x-2=0$ $5x-2=0y$ $0y=5x-2$ In order to find the slope, we should divide both sides by $0$. In this case we would find that: $m=\frac{5}{0}$ Also, $5x-2=0$ $5x=2$ $x=\frac{2}{5}$ Slope: not possible to evaluate y-intercept: it is a vertical line with $x=\frac{2}{5}$. That is, there is no point on the line when $x=0$