Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - 2.1 - Linear Equations in Two Variables - 2.1 Exercises - Page 169: 40


$(-1,-5)$, $(0,-\frac{19}{4})$, $(7,-3)$

Work Step by Step

Use the point-slope form: $y-y_1=m(x-x_1)$, where $m$ is the slope and $(x_1,y_1)$ is a point on the line. $y-(-4)=\frac{1}{4}(x-3)$ $y+4=\frac{1}{4}x-\frac{3}{4}$ $y=\frac{1}{4}x-\frac{19}{4}$ Now, choose three different values for $x$ to find three different points on the line. For example, $x=-1$, $x=0$ and $x=7$: $x=-1$: $y=\frac{1}{4}(-1)-\frac{19}{4}=-\frac{20}{4}=-5$ Point: $(-1,-5)$ $x=0$: $y=\frac{1}{4}(0)-\frac{19}{4}=-\frac{19}{4}$ Point: $(0,-\frac{19}{4})$ $x=7$: $y=\frac{1}{4}(7)-\frac{19}{4}=-\frac{12}{4}=-3$ Point: $(7,-3)$
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