Answer
$a_{n} = -\frac{1}{3}n + \frac{31}{3}$
Work Step by Step
$d = \frac{6-8}{13-7} = -\frac{1}{3}$
$a_{1} = a_{7} - 6d = 10$
$a_{n} = 10. - \frac{(n-1)}{3} = \frac{n}{3} + \frac{31}{3}$
(Since $a_{n} = a_{1} + (n-1)*d$)
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - Review Exercises - Page 840: 28
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