Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - Review Exercises - Page 840: 13



Work Step by Step

$\sum_{j=1}^{4} \frac{6}{j^2}=\frac{6}{1^2}+\frac{6}{2^2}+\frac{6}{3^2}+\frac{6}{4^2}=\frac{6}{1}+\frac{6}{4}+\frac{6}{9}+\frac{6}{16}=\frac{144}{24}+\frac{36}{24}+\frac{16}{24}+\frac{9}{24}=\frac{205}{24}$
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