Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.4 - Mathematical Induction - 11.4 Exercises - Page 807: 49



Work Step by Step

The sum of the fourth powers of the first $n$ integers can be obtained by the following formula: $\frac{n(n+1)(2n+1)(3n^2+3n-1)}{30}.$ Thus the sum:$\frac{5(5+1)(2( 5)+1)(3(5)^2+3(5)-1)}{30}=\frac{5(6)(11)(89)}{30}=11\cdot89=979$
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