# Chapter 11 - 11.4 - Mathematical Induction - 11.4 Exercises - Page 807: 47

$91$

#### Work Step by Step

The sum of the squares of the first $n$ integers can be obtained by the following formula: $\frac{n(n+1)(2n+1)}{6}.$ Thus the sum:$\frac{6(6+1)(2(6)+1}{6}=7\cdot13=91$

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