## Algebra and Trigonometry 10th Edition

$R+L+I=120$ and $2.5 R+4L+2I=300$ and $R=2(L+I)$
We are given that there are $120$ flowers. Let us suppose that $R$ is the number of roses, $L$ is the number of lilies and $I$ is the number of Irises. Therefore, $R+L+I=120$ Further, the total price of the flowers is $\$ 300$. Thus,$ 2.5 R+4L+2I=300$Next,$R=2(L+I)\$