#### Answer

x = 1, 3

#### Work Step by Step

Solve the individual equaions obtained after breaking the expression into two separate equations.
Case 1:
$x^2-3=-2x$
$x^2+2x-3=0$
(x+3)(x-1)=0
x = -3, 1
We plug in the Case 1 equation to see -3 is extraneous solution. Hence x=1.
Case 2:
$x^2-3=2x$
$x^2-2x-3=0$
(x-3)(x+1)=0
x = 3, -1
Plug in the Case 2 equation to see -1 is extraneous solution. Hence x=3