Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - Review Exercises - Page 154: 82


Solutions: $x=0$ and $x=\frac{3}{2}$

Work Step by Step

$4x^3-6x^2=0$ $2x^2(2x-3)=0$ $2x^2=0$ $x^2=0$ $x=0$ or $2x-3=0$ $2x=3$ $x=\frac{3}{2}$ Testing: - $x=0$: $4(0)^3-6(0)^2=0-0=0$ - $x=\frac{3}{2}$: $4(\frac{3}{2})^3-6(\frac{3}{2})^2=4~\frac{27}{8}-6~\frac{9}{4}=\frac{108}{8}-\frac{54}{4}=\frac{27}{2}-\frac{27}{2}=0$
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