Answer
It is not possible.
More than 2 x-intercepts is equivalent to more than 2 solutions.
Work Step by Step
$y=ax^2+bx+c$
In the x-intercepts $y=0$:
$0=ax^2+bx+c$
The solution equation is:
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}$ that allows for no more than two solutions.
