Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 113: 129


It is not possible. More than 2 x-intercepts is equivalent to more than 2 solutions.

Work Step by Step

$y=ax^2+bx+c$ In the x-intercepts $y=0$: $0=ax^2+bx+c$ The solution equation is: $x=\frac{-b±\sqrt {b^2-4ac}}{2a}$ that allows for no more than two solutions.
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