Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 113: 118b



Work Step by Step

We have $C=0.45x^2-1.65x+50.75$ Plug in $x=10$, $\implies 0.45(10)^2-1.65(10)+50.75=79.25$ Plug in $x=20$, $\implies 0.45(20)^2-1.65(20)+50.75=197.75$ The oxygen consumption is increased by approximately $\frac{197.75}{79.25}\approx 2.495$
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