## Algebra and Trigonometry 10th Edition

time taken $\approx$ 5.86 seconds
$Change in height = H-h = ut + \frac{1}{2}at^{2}$ Initial velocity (u) for free fall=0 Final height (H) is 0 Initial height (h) is 550 The time taken to reach the ground is given as t Plug in values $0= 550 + 0*t -16t^{2}$ $550 =16t^{2}$ $t^{2}=550/16$ $t=\sqrt {550/16}$$\approx$ 5.86 seconds