## Algebra and Trigonometry 10th Edition

$\frac{1}{3}b^{2} + \frac{1}{2}b$
Area of a triangle = 1/2 * base * height Hence Area = $\frac{1}{2}(b)(\frac{2}{3}b+1) = \frac{1}{3}b^{2} + \frac{1}{2}b$