Answer
$\frac{1}{3}b^{2} + \frac{1}{2}b$
Work Step by Step
Area of a triangle = 1/2 * base * height
Hence Area = $\frac{1}{2}(b)(\frac{2}{3}b+1) = \frac{1}{3}b^{2} + \frac{1}{2}b$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.3 - Modeling with Linear Equations - 1.3 Exercises - Page 97: 30
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