#### Answer

$8n^{2} + 8n + 4$

#### Work Step by Step

If the first even is 2n, the next is 2n+2. The sum of their squares is:
$(2n)^{2} + (2n+2)^{2} = $ = $4n^{2} + 4n^{2} + 8n + 4$ = $8n^{2} + 8n + 4$

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Published by
Cengage Learning

ISBN 10:
9781337271172

ISBN 13:
978-1-33727-117-2

$8n^{2} + 8n + 4$

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