## Algebra and Trigonometry 10th Edition

$8n^{2} + 8n + 4$
If the first even is 2n, the next is 2n+2. The sum of their squares is: $(2n)^{2} + (2n+2)^{2} =$ = $4n^{2} + 4n^{2} + 8n + 4$ = $8n^{2} + 8n + 4$