Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.2 - Linear Equations in One Variable - 1.2 Exercises - Page 89: 78

Answer

false

Work Step by Step

$x=2$ cannot be a solution because the denominator cannot be $0$. Let's multiply both sides by $x-2$, then: $2(x-2)-1=3\\2(x-2)=4\\x-2=2\\x=4$ Thus $x=4$ is a good solution, so the statement is false.
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