## Algebra and Trigonometry 10th Edition

$y+1=\displaystyle \frac{3}{4}x\qquad$subtract 1 from both sides $y=\displaystyle \frac{3}{4}x-1$ Calculate the corresponding y for each value of x $\left[\begin{array}{ccccccc} x & -2 & 0 & 1 & 4/3 & 2\\ y=\frac{3}{4}x-1 & \frac{3}{4}(-2)-1 & \frac{3}{4}(0)-1 & \frac{3}{4}(1)-1 & \frac{3}{4}(\frac{4}{3})-1 & \frac{3}{4}(2)-1\\ & =-\frac{5}{2} & =-1 & =-\frac{1}{4} & =0 & =\frac{1}{2}\\ \hline & & & & & \\ (x,y) & (-2,-2.5) & (0,-1) & (1,-0.25) & (\frac{4}{3},0) & (2,0.5) \end{array}\right]$ Plot the points and draw a line through them.