## Algebra and Trigonometry 10th Edition

The point (-1,1) lies on the graph of $y=3-2x^2$, but the point (-2,11) does not.
$y=3-2x^2$ (a) Point: (-1,1): $1=3-2(-1)^2$ $1=3-2(1)$ $1=3-2$ $1=1$ Correct. (b) Point: (-2,11): $11=3-2(-2)^2$ $11=3-2(4)$ $11=3-8$ $11=-5$ Incorrect.