## Algebra: A Combined Approach (4th Edition)

$16$-pound force
Let $F$ be the force of the wind. Let $A$ be the surface area. Let $s$ be the speed of wind. $F=kAs$ $F=20; A=12; s=10$ $20 =k(12)(10)$ $k=\frac{1}{6}$ $F=\frac{1}{6}As$ $A=8; s=12$ $F=\frac{1}{6}(8)(12)$ $F=16$-pound force