#### Answer

$a=kbc$

#### Work Step by Step

Because $a$ varies jointly as $b$ and $c$, we equate $a$ to a constant multiple of $b$ and $c$:
$a=kbc$.

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$a=kbc$

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