#### Answer

$15\pi$ cubic inches

#### Work Step by Step

Let $V$ be the volume of a cone.
Let $h$ be the height of a cone.
Let $r$ be the radius of a cone.
$V=khr^2$
$V=32\pi; h=6; r=4$
$32\pi =k(6)(4)^2$
$k=\frac{\pi }{3}$
$V=\frac{\pi }{3}hr^2$
$h=5; r=3$
$V=\frac{\pi }{3}(5)(3)^2$
$V=15\pi$ cubic inches