Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Test: 8



Work Step by Step

$\frac{ay+3a+2y+6}{ay+3a+5y+15}$ =$\frac{a(y+3)+2(y+3)}{a(y+3)+5(y+3)}$ =$\frac{(y+3)(a+2)}{(y+3)(a+5)}$ =$\frac{(a+2)}{(a+5)}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.