Answer
$\frac{4y^2 + 13y - 15}{(y + 5)(y + 1)(y + 4)}$
Work Step by Step
$\frac{4y}{y^2 + 6y + 5}$ - $\frac{3}{y^2 +5y + 4}$
= $\frac{4y}{(y + 5)(y + 1)}$ - $\frac{3}{(y + 4)(y + 1)}$
= $\frac{4y(y + 4)}{(y + 5)(y + 1)(y + 4)}$ - $\frac{3(y + 5)}{(y + 4)(y + 1)(y + 5)}$
= $\frac{4y(y + 4) - 3(y + 5)}{(y + 5)(y + 1)(y + 4)}$
= $\frac{4y^2 + 16y - 3y - 15}{(y + 5)(y + 1)(y + 4)}$
= $\frac{4y^2 + 13y - 15}{(y + 5)(y + 1)(y + 4)}$