Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Test - Page 561: 15

Answer

$\frac{2(x + 5)}{x(y + 5)}$

Work Step by Step

$\frac{x^2 - 9}{x^2 - 3x}$ $\div$ $\frac{xy + 5x + 3y + 15}{2x + 10}$ = $\frac{(x + 3)(x - 3)}{x(x - 3)}$ $\div$ $\frac{y(x + 3) + 5(x + 3)}{2(x + 5)}$ = $\frac{(x + 3)}{x}$ $\div$ $\frac{(y + 5)(x + 3)}{2(x + 5)}$ = $\frac{(x + 3)}{x}$ $\times$ $\frac{2(x + 5)}{(y + 5)(x + 3)}$ = $\frac{2(x + 5)}{x(y + 5)}$
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