## Algebra: A Combined Approach (4th Edition)

Dimensions are: 20-foot by 12-foot Thus area of room = 20(12) = 240 square feet. Since every student needs a minimum of 9 square feet, total students that can be accommodate are : $\frac{240}{9}$ = 26.667. But, students cannot be in fractions, thus the nearest number lower than 26.667 is 26. Thus the room can accommodate 26 students.