Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.6 - Proportions and Problem Solving with Rational Equations - Exercise Set - Page 538: 27

Answer

10 mph for the first portion 8 mph for the cooldown portion

Work Step by Step

distance = rate * time $20 = r*t$ $16 = (r-2)*t$ $20 = r*t$ $20/r = r*t/r$ $20/r = t$ $16 = (r-2)*t$ $16/(r-2)=(r-2)*t/(r-2)$ $16/(r-2) = t$ $20/r = 16/(r-2)$ $20*(r-2)=16r$ $20r-40=16r$ $4r-40=0$ $4r=40$ $4r/4=40/4$ $r=10$ $20 = r*t$ $20 = 10*t$ $20/10 = 10t/10$ $2=t$ $16 = (r-2)*t$ $16 = (10-2)*2$ $16=8*2$ (true statement)
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