## Algebra: A Combined Approach (4th Edition)

$\dfrac{y}{2y+2}+\dfrac{2y-16}{4y+4}=\dfrac{2y-3}{y+1}$ Take out common factor $2$ from the denominator of the first fraction and common factor $4$ from the denominator of the second fraction: $\dfrac{y}{2(y+1)}+\dfrac{2y-16}{4(y+1)}=\dfrac{2y-3}{y+1}$ Multiply the whole equation by $8(y+1)$ $8(y+1)\Big[\dfrac{y}{2(y+1)}+\dfrac{2y-16}{4(y+1)}=\dfrac{2y-3}{y+1}\Big]$ $4y+4y-32=16y-24$ Take all terms to the right side of the equation and simplify it by combining like terms: $16y-24-4y-4y+32=0$ $8y+8=0$ Solve for $y$: $8y=-8$ $y=-\dfrac{8}{8}$ $y=-1$ This is the solution found. Substituting $y=-1$ in the original equation makes all denominator $0$. Knowing that, we conclude that this equation has no solution.