Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.5 - Solving Equations Containing Rational Expressions - Exercise Set - Page 524: 35


the solutions are -2 and 8

Work Step by Step

$\frac{t}{t-4}$=$\frac{t+4}{6}$ 6(t-4)$\frac{t}{t-4}$=6(t-4)$\frac{(t+4)}{6}$ 6t=$t^{2}$-16 0=$t^{2}$-6t-16 0=$t^{2}$+2t-8t-16 0=t(t+2)-8(t+2) 0=(t-8)(t+2) t-8=0 or t+2=0 t=8 or t=-2 The solutions are -2 and 8 Check Let t=-2 $\frac{t}{t-4}$=$\frac{t+4}{6}$ $\frac{-2}{-2-4}$=$\frac{-2+4}{6}$ $\frac{-2}{-6}$=$\frac{2}{6}$ $\frac{2}{6}$=$\frac{2}{6}$ Let t=8 $\frac{t}{t-4}$=$\frac{t+4}{6}$ $\frac{8}{8-4}$=$\frac{8+4}{6}$ $\frac{8}{4}$=$\frac{12}{6}$ 2=2
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