Algebra: A Combined Approach (4th Edition)

(y-2)$\frac{2y}{y-2}$-(y-2)$\frac{4}{y-2}$=4(y-2) 2y-4=4y-8 -4+8=4y-2y 4=2y 2=y 2 cannot be a solution because $\frac{2y}{y-2}$ is undefined