Answer
No solution
Work Step by Step
2+$\frac{3}{a-3}$=$\frac{a}{a-3}$
(a-3)(2+$\frac{3}{a-3}$)=(a-3)$\frac{a}{a-3}$
2(a-3)+(a-3)$\frac{3}{a-3}$=a
2a-6+3=a
2a-3=a
2a-a=3
a=3
The number 3 cannot be the solution, because $\frac{3}{a-3}$
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