Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.5 - Solving Equations Containing Rational Expressions - Exercise Set - Page 523: 11


x = 3

Work Step by Step

$\frac{x-3}{5}$+$\frac{x-2}{2}$=$\frac{1}{2}$ 10($\frac{x-3}{5}$+$\frac{x-2}{2}$)=10$\frac{1}{2}$ 10$\frac{x-3}{5}$+10$\frac{x-2}{2}$=10$\frac{1}{2}$ 2(x-3)+5(x-2)=5 2x-6+5x-10=5 7x-16=5 7x=5+16 7x=21 x=3 The solution is 3 Check Let x=3 $\frac{x-3}{5}$+$\frac{x-2}{2}$=$\frac{1}{2}$ $\frac{3-3}{5}$+$\frac{3-2}{2}$=$\frac{1}{2}$ 0+$\frac{1}{2}$=$\frac{1}{2}$ $\frac{1}{2}$=$\frac{1}{2}$
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