#### Answer

$\dfrac{-2x}{x^{3}-8x}\div\dfrac{3x}{x^{3}-8x}=-\dfrac{2}{3}$

#### Work Step by Step

$\dfrac{-2x}{x^{3}-8x}\div\dfrac{3x}{x^{3}-8x}$
Evaluate the division of the two rational expressions and then simplify:
$\dfrac{-2x}{x^{3}-8x}\div\dfrac{3x}{x^{3}-8x}=\dfrac{(-2x)(x^{3}-8x)}{(3x)(x^{3}-8x)}=\dfrac{-2x}{3x}=-\dfrac{2}{3}$