#### Answer

$\dfrac{-2x}{x^{3}-8x}+\dfrac{3x}{x^{3}-8x}=\dfrac{1}{x^{2}-8}$

#### Work Step by Step

$\dfrac{-2x}{x^{3}-8x}+\dfrac{3x}{x^{3}-8x}$
Evaluate the sum of the two rational expressions:
$\dfrac{-2x}{x^{3}-8x}+\dfrac{3x}{x^{3}-8x}=\dfrac{-2x+3x}{x^{3}-8x}=\dfrac{x}{x^{3}-8x}=...$
Take out common factor $x$ in the denominator and simplify:
$...=\dfrac{x}{x(x^{2}-8)}=\dfrac{1}{x^{2}-8}$