Answer
$\dfrac{x^{2}+5x}{x^{2}-25}\cdot\dfrac{3x-15}{x^{2}}=\dfrac{3}{x}$
Work Step by Step
$\dfrac{x^{2}+5x}{x^{2}-25}\cdot\dfrac{3x-15}{x^{2}}$
Factor both rational expressions completely:
$\dfrac{x^{2}+5x}{x^{2}-25}\cdot\dfrac{3x-15}{x^{2}}=\dfrac{x(x+5)}{(x+5)(x-5)}\cdot\dfrac{3(x-5)}{x^{2}}=...$
Evaluate the product and simplify by removing the factors that appear both in the numerator and the denominator of the resulting expression:
$...=\dfrac{3x(x+5)(x-5)}{x^{2}(x+5)(x-5)}=\dfrac{3}{x}$
