Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Review: 45



Work Step by Step

$\dfrac{x-3}{x+1}-\dfrac{x-6}{x+5}=0$ Multiply the whole equation by $(x+1)(x+5)$: $(x+1)(x+5)\Big(\dfrac{x-3}{x+1}-\dfrac{x-6}{x+5}=0\Big)$ $(x-3)(x+5)-(x-6)(x+1)=0$ Evaluate both products: $x^{2}+2x-15-x^{2}+5x+6=0$ Simplify the equation by combining like terms: $7x-9=0$ Solve for $x$: $7x=9$ $x=\dfrac{9}{7}$ The original equation is not undefined for this value of $x$, so the solution to this equation is $x=\dfrac{9}{7}$
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