Answer
$\dfrac{9x+7}{6x^{2}}-\dfrac{3x+4}{6x^{2}}=\dfrac{2x+1}{2x^{2}}$
Work Step by Step
$\dfrac{9x+7}{6x^{2}}-\dfrac{3x+4}{6x^{2}}$
Evaluate the substraction:
$\dfrac{9x+7}{6x^{2}}-\dfrac{3x+4}{6x^{2}}=\dfrac{(9x+7)-(3x+4)}{6x^{2}}=...$
$...=\dfrac{9x+7-3x-4}{6x^{2}}=\dfrac{6x+3}{6x^{2}}=...$
Take out common factor $3$ from the numerator and simplify:
$...=\dfrac{3(2x+1)}{6x^{2}}=\dfrac{2x+1}{2x^{2}}$